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3n^2-37n-24=0
a = 3; b = -37; c = -24;
Δ = b2-4ac
Δ = -372-4·3·(-24)
Δ = 1657
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-37)-\sqrt{1657}}{2*3}=\frac{37-\sqrt{1657}}{6} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-37)+\sqrt{1657}}{2*3}=\frac{37+\sqrt{1657}}{6} $
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